Biochemistry A Short Course First Edition by John L. Tymoczko – Test Bank
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Sample Questions
Chapter
4 Protein Three-Dimensional Structure
Matching Questions
Use the following to answer questions 1–10:
Choose the correct answer from the list below. Not all of the
answers will be used.
1. a) amino
2. b)
water
3. c)
protons
4. d)
DNA
5. e)
secondary structure
6. f)
tertiary structure
7. g)
Ramachandran
8. h)
RNA
9. i)
domain
10.
j) cystine
11.
k) proline
12.
l) Sanger
13.
m) d amino acids
14.
n) cysteine
|
1. |
When a peptide bond is formed between
two amino acids, a(n) ____________molecule is lost. |
|
|
|
Ans: |
b |
|
|
Section: 4.1 |
|
|
2. |
____________: Codes for the sequence of
amino acids. |
|
|
|
Ans: |
d |
|
|
Section: Introduction |
|
|
3. |
According to convention, ____________
is the terminus drawn on the left side of a peptide. |
|
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|
Ans: |
a |
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Section: 4.1 |
|
|
4. |
Two amino acids undergo oxidation to
form a dimer called ____________. |
|
|
|
Ans: |
j |
|
|
Section: 4.1 |
|
|
5. |
Changes in ____________ create amyloid
fibers, which are insoluble and are the source of mad cow disease, Alzheimer
disease, and Parkinson disease. |
|
|
|
Ans: |
e |
|
|
Section: 4.5 |
|
|
6. |
____________: Compact regions that may
be connected by a flexible segment of polypeptide chain. |
|
|
|
Ans: |
i |
|
|
Section: 4.3 |
|
|
7. |
____________: This amino acid residue
disrupts the α helix because its side chain contains a unique ring structure
that restricts bond rotations. |
|
|
|
Ans: |
k |
|
|
Section: 4.2 |
|
|
8. |
The plot that allows one to investigate
the likely orientation of certain amino acid pairs is called the
____________. |
|
|
|
Ans: |
g |
|
|
Section: 4.1 |
|
|
9. |
____________: The type of structure to
which α helices, β sheets, and turns are referred. |
|
|
|
Ans: |
e |
|
|
Section: 4.2 |
|
|
10. |
The overall 3D-structure of a single
polypeptide chain is referred to as ____________. |
|
|
|
Ans: |
f |
|
|
Section: 4.3 |
|
Fill-in-the-Blank
Questions
|
11. |
The of
a disulfide bridge results in a separation of two protein chains. |
|
|
Ans:
oxidation
Section
4.1 |
|
12. |
The peptide bond is also known as a(n) . |
|
|
Ans: amide
bond
Section
4.1 |
|
13. |
Peptides differ from proteins in . |
|
|
Ans: the number of amino acid
residues
Section 4.1 |
|
14. |
Due to the side chain steric clash,
almost all peptide bonds are in
their configuration. |
|
|
Ans: trans
Section
4.1 |
|
15. |
The secondary structure that is
stabilized by CO and NH hydrogen bonding within the peptide chain is
the . |
|
|
Ans: alpha
helix
Section 4.2 |
|
16. |
The indicates
the left- or right-handedness of an α helix. |
|
|
Ans: screw
sense
Section 4.2 |
|
17. |
is a fibrous protein and is the primary component of
wool and hair. |
|
|
Ans:
α-keratin
Section
4.2 |
|
18. |
Every third residue in the protein
collagen is . |
|
|
Ans:
glycine
Section
4.2 |
|
19. |
Disulfide bonds in proteins can be
reduced to free sulfhydryl groups by reagents such as . |
|
|
Ans:
β-mecaptoethanol
Section 4.3 |
|
20. |
The β-sheet
structure occurs when the two strands are oriented in opposite directions (N
→ C). |
|
|
Ans:
antiparallel
Section 4.3 |
|
21. |
A protein whose peptide backbone is
mostly extended and hydrogen bonded to different strands of the protein is
composed mostly of the secondary
structure. |
|
|
Ans:
β-sheet
Section 4.3 |
|
22. |
A protein is considered to be when
it is converted into a randomly coiled structure without its normal activity. |
|
|
Ans:
denatured
Section
4.4 |
|
23. |
is the major fibrous protein present in skin, bone,
tendon, cartilage, and teeth. |
|
|
Ans:
Collagen
Section
4.3 |
|
24. |
Collagen contains ,
a modified amino acid. |
|
|
Ans:
hydroxyproline
Section 4.3 |
|
25. |
Compact, globular proteins are
typically water and consist mostly
of secondary structure. |
|
|
Ans: soluble; an alpha helical
Section 4.3 |
|
26. |
refers to the spatial arrangement of subunits and the
nature of their interactions. |
|
|
Ans: Quaternary
structure Section 4.3 |
Multiple-Choice Questions
|
27. |
What determines a protein’s function? |
|
|
A) its structure |
|
|
B) its gene sequence |
|
|
C) N-terminal amino acids |
|
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D) None of the above. |
|
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E) All of the above. |
|
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Ans:
A
Section: Introduction |
|
28. |
What is the approximate mass of a
protein containing 200 amino acids? (Assume there are no other protein modifications.) |
|
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A) 20,000 |
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B) 11,000 |
|
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C) 22,000 |
|
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D) 222,000 |
|
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E) None of the above. |
|
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Ans:
C
Section: 4.1 |
|
29. |
Key properties of proteins include: |
|
|
A) a wide range of functional groups. |
|
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B) an ability to possess either rigid
or flexible structures as dictated by functional requirements. |
|
|
C) the ability to interact with other
proteins. |
|
|
D) A and B. |
|
|
E) All of the above. |
|
|
Ans:
E
Section: 4.1 |
|
30. |
Why is the peptide bond planar? |
|
|
A) Bulky side chains prevent free
rotation around the bond. |
|
|
B) It exhibits partial double-bond
character, preventing rotation. |
|
|
C) Hydrogen bonding between the NH and
C=O groups limits movement. |
|
|
D) None of the above. |
|
|
E) All of the above. |
|
|
Ans: B
Section: 4.1 |
|
31. |
The configuration of most α-carbon
atoms of amino acids linked in a peptide bond is: |
|
|
A) cis. |
|
|
B) circular. |
|
|
C) parallel. |
|
|
D) trans. |
|
|
E) perpendicular. |
|
|
Ans:
D
Section: 4.1 |
|
32. |
What structure(s) did Pauling and Corey
predict in 1951? |
|
|
A) α helix |
|
|
B) β sheet |
|
|
C) β turn |
|
|
D) A, B, and C |
|
|
E) A and B |
|
|
Ans:
E
Section: 4.2 |
|
33. |
Which of the following protein(s)
contain examples of α-helical character? |
|
|
A) keratin |
|
|
B) ferritin |
|
|
C) myosin |
|
|
D) tropomyosin |
|
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E) All of the above. |
|
|
Ans:
E
Section: 4.2 |
|
34. |
Which of the following amino acid
residues would most likely be buried in the interior of a water-soluble,
globular protein? |
|
|
A) aspartate |
|
|
B) serine |
|
|
C) phenylalanine |
|
|
D) lysine |
|
|
E) glutamine |
|
|
Ans:
C
Section 4.3 |
|
35. |
Where are β turns and loops often
found? |
|
|
A) in a hydrophobic pocket |
|
|
B) on the interior cleft |
|
|
C) at the protein interface with ligand |
|
|
D) on the surface of proteins |
|
|
E) None of the above. |
|
|
Ans:
D
Section: 4.3 |
|
36. |
The folding of a protein into its
native shape can best be described as: |
|
|
A) a random event. |
|
|
B) a random event catalyzed by ribosome
proteins to maintain a low energy structure. |
|
|
C) a series of controlled folds with a
few random-shaped structures. |
|
|
D) a series of repeatable random events
where the lowest energy structure is maintained. |
|
|
E) an event where the highest possible
energy state is stabilized with discrete folding intermediates. |
|
|
Ans:
D
Section: 4.5 |
|
37. |
Your study group is trying to identify
differences in the four levels of protein structure. Which of the following
would you say is true of important stabilizing forces in secondary structure
but not tertiary structure? |
|
|
A) The structure is stabilized by ionic
attractions between oppositely charged side chains. |
|
|
B) The structure is stabilized by
H-bonding between polar side chains. |
|
|
C) The structure is stabilized by
hydrophobic interactions between nonpolar side chains. |
|
|
D) The structure is stabilized by
H-bonding between the oxygen of the backbone carbonyl and the hydrogen of the
backbone amine. |
|
|
E) None of these differentiate between
secondary and tertiary structure. |
|
|
Ans:
D
Sections: 4.2 and 4.3 |
|
38. |
A clinician friend comes to you and
tells you she has a patient that she thinks has some sort of defect in the
collagen structure. She wants to know what kinds of structural differences
there might be. Which of the following is NOT true for defects leading to
scurvy or brittle bone disease? |
|
|
A) Proline residues are not
hydroxylated. |
|
|
B) Glycine is replaced by other amino
acids. |
|
|
C) Proyloyl hydroxylase activity is
deficient. |
|
|
D) Accumulation of defective collagen
causes cell death. |
|
|
E) All of the above are true. |
|
|
Ans:
E
Section: 4.2 |
|
39. |
All of the following would disrupt
quaternary structure except: |
|
|
A) increase the temperature. |
|
|
B) decrease the pH. |
|
|
C) add 8 m Urea. |
|
|
D) treat with ascorbic acid (vitamin
C). |
|
|
E) treat with β-mercaptoethanol. |
|
|
Ans:
D
Section: 4.4 |
|
40. |
Which of the following secondary
structures would you expect to find on the surface of a globular protein? |
|
|
A) α helix |
|
|
B) β sheet |
|
|
C) loops between two α-helices |
|
|
D) none of the above because water
would disrupt the hydrogen bonding that stabilizes these structures |
|
|
E) A, B, and C as long as the polar and
charged amino acid side chains face the surface of the protein |
|
|
Ans: E
Section:
4.2 |
|
41. |
The metamorphic protein lymphotactin
undergoes changes in _____what_______ structure in order to carry out its
full biochemical activity? |
|
|
A) primary and therefore also tertiary |
|
|
B) primary, secondary, and tertiary |
|
|
C) quaternary (subunits separate and
carry out individual activities) |
|
|
D) secondary and tertiary |
|
|
E) primary, secondary, tertiary, and
quaternary |
|
|
Ans:
D
Section: 4.5 |
Short-Answer Questions
|
42. |
How does a protein’s amino acid
sequence influence the tertiary structure? |
|
|
|
Ans: |
A protein will spontaneously fold into
a three-dimensional structure determined by the amino acid sequence. |
|
|
Section: Introduction |
|
|
43. |
What is the advantage of protein
interaction and assembly with other proteins? |
|
|
|
Ans: |
When proteins interact or assemble, new
functions and specificity become available. Protein interactions allow new
binding sites at the assembly interface, and provide multifunctional activity
and specificity, such as that found in polymerases and signal transduction. |
|
|
Section: Introduction |
|
|
44. |
How does the protein backbone add to
structural stability? |
|
|
|
Ans: |
The protein backbone contains the
peptide bond, which has NH molecules and C=O (ketone) groups. Hydrogen-bond
formation between the hydrogen on the nitrogen and the oxygen support the
protein conformation. |
|
|
Section: 4.2 |
|
|
45. |
Why are all the theoretical combinations
of phi and psi not possible? |
|
|
|
Ans: |
Steric hindrances of the side chains
make certain combinations and angles impossible. |
|
|
Section: 4.2 |
|
|
46. |
Describe some of the features of an α
helix. |
|
|
|
Ans: |
The α helix is a coil stabilized by
intrachain hydrogen bonds between the carbonyl oxygen of a residue and the
amide hydrogen of the fourth residue away. There are 3.6 amino acids per
turn. The hydrogen bonds are between amino acid residues that have two intervening
residues. Thus, these amino acid residues are found on the same side of the
coil. The helix is almost always right-handed, although left-handed helices
are, in theory, possible. |
|
|
Section: 4.2 |
|
|
47. |
What is the “hydrophobic effect” as it relates
to protein structure? |
|
|
|
Ans: |
The three-dimensional structure of a
water-soluble protein is stabilized by the tendency of hydrophobic groups to
assemble in the interior of the molecule. |
|
|
Section: 4.3 |
|
|
48. |
What are the key characteristics that
make the peptide bond important to protein folding/structure? |
|
|
|
Ans: |
The resonance of the amide bond creates
a planar, rigid region of the peptide backbone with the R groups on opposite
sides of the peptide bond. This results in a limit to the types and angles of
conformation, allowing a predictable folding pattern. |
|
|
Section: 4.1 |
|
|
49. |
What are prions? |
|
|
|
Ans: |
Prions are proteins that can assume
(after infection or by other causes) a new protein structure that is self-propagating.
Prion diseases have several variants, at least one of which is fatal to
humans. |
|
|
Section: 4.5 |
|
|
50. |
In the ribonuclease experiments
performed by Anfinsen, what was the significance of the presence of the
reducing agent β-mercaptoethanol? |
|
|
|
Ans: |
The reducing agent reduced incorrectly
paired disulfide bonds, allowing them to reform with the correct pairing
until the most stable conformation of the protein had been obtained. |
|
|
Section: 4.5 |
|
|
51. |
What is the advantage of having certain
regions of partially correct folded regions? |
|
|
|
Ans: |
If some regions interact
preferentially, lending stability to certain conformations as the protein
folds, they can impact the overall structure of the protein. |
|
|
Section: 4.3 |
|
|
52. |
A primary sequence of a protein
contains a run of reasonably small amino acids, containing few branched amino
acids or serines. This sequence ends in a proline. What can you deduce from
this information? |
|
|
|
Ans: |
The sequence is likely an α helix. The
smaller amino acids do not sterically hinder the side groups on the outside
of the helix and the absence of amino acids that would interfere with the
helix are all evidence for this secondary structure. The proline is likely to
be the end of the sequence. |
|
|
Section: 4.2 |
|
|
53. |
What is the sequence of amino acids
found in collagen? What is the significance of the sequence and what is the
complication of scurvy? |
|
|
|
Ans: |
Gly-Pro-Pro. The small side group of
the glycine allows for a tight screw turn for this atypical helix. The
prolines are important to stabilize tight three-amino-acid helices. In
addition, the prolines are also hydroxylated by an enzyme that requires
ascorbic acid to maintain activity. Without the hydroxylation of collagen by
prolylhydroxylase, the collagen superstructure is less stable and results in
adverse flexibility of the connective tissues (scurvy). |
|
|
Section: 4.2 |
|
|
54. |
Prion diseases are often latent; that
is, those with prion diseases are asymptomatic for many years after their
initial infection. What causes this latency? |
|
|
|
Ans: |
Prion diseases are protein based; more
specifically, protein-structure based. Because it takes time to convert the
prion protein from the soluble, mostly helical form to the beta-strand,
insoluble form, there is lag time before enough proteins are converted to the
polymer, which causes cell injury This characteristic of prion diseases makes
it difficult to diagnose before it is too late. |
|
|
Section: 4.5 |
|
Chapter 7 Kinetics and Regulation
Matching
Questions
Use the following to answer questions 1-10:
Choose the correct answer from the list below. Not all of the
answers will be used.
1. a)
first-order reaction
2. b)
second-order reaction
3. c)
metabolism
4. d)
ensemble
5. e)
biomolecular
6. f)
turnover number
7. g)
Michaelis
8. h)
equilibrium
9. i)
sequential
10.
j) kinetics
11.
k) initial reaction velocity
12.
l) allosteric
13.
m) ping-pong
|
1. |
____________is a complex array of
enzyme catalyzed reactions organized in multiple pathways. |
|
|
|
Ans: |
c |
|
|
Section: Introduction |
|
|
2. |
_______________ is the study of rates
of chemical reactions. |
|
|
|
Ans: |
j |
|
|
Section: 7.1 |
|
|
3. |
A reaction that is directly
proportional to the concentration of reactant is a ____________. |
|
|
|
Ans: |
a |
|
|
Section: 7.1 |
|
|
4. |
A reaction with two substrates is
considered a ____________ reaction. |
|
|
|
Ans: |
e |
|
|
Section7.1 |
|
|
5. |
At ____________ there will be no net
change in the concentration of substrate or product. |
|
|
|
Ans: |
h |
|
|
Section: 7.2 |
|
|
6. |
The value Vo is called the
____________. |
|
|
|
Ans: |
k |
|
|
Section: 7.2 |
|
|
7. |
The kcat is often referred to as the ____________. |
|
|
|
Ans: |
f |
|
|
Section: 7.2 |
|
|
8. |
The property that describes the
enzyme-substrate interaction is measured by what constant? |
|
|
|
Ans: |
g |
|
|
Section: 7.2 |
|
|
9. |
____________ Enzymes that do not obey
Michaelis–Menten kinetics. |
|
|
|
Ans: |
l |
|
|
Section: 7.3 |
|
|
10. |
____________ Experiments that determine
the kinetics of a population of enzyme molecules. |
|
|
|
Ans: |
d |
|
|
Section: 7.4 |
|
Fill-in-the-Blank
Questions
|
11. |
One way to measure the rate of an
enzymatic reaction is to measure the loss of over
time. |
|
|
Ans: substrate
Section: 7.1 |
|
|
|
|
12. |
Reactions that have more than two
reactants or substrates are considered reactions. |
|
|
Ans:
second-order Section: 7.1 |
|
|
|
|
13. |
The rule
states that all subunits in an allosteric enzyme must be in either the R or
the R state; no hybrids. |
|
|
Ans: symmetry
Section: 7.3 |
|
|
|
|
14. |
The Michaelis–Menten model assumes
that is the rate constant
ignored because P has not accumulated. |
|
|
Ans: k–2 Section: Appendix |
|
|
|
|
15. |
is directly dependent on enzyme concentration. |
|
|
Ans: Vmax Section: 7.2 |
|
|
|
|
16. |
An enzyme will be most sensitive to
changes in cellular substrate concentration when the concentration is . |
|
|
Ans: near the KM Section:
7.2 |
|
|
|
|
17. |
The type of inhibition where the
product of one enzyme inhibits another enzyme that acts earlier in a
metabolic pathway is considered a(an) inhibitor. |
|
|
Ans:
feedback Section: 7.3 |
|
18. |
Allosteric enzymes can be identified
because the plot of initial velocity, V0, versus substrate
concentration, S, is not hyperbolic but -shaped. |
|
|
Ans:
sigmoidal Section: 7.3 |
|
19. |
Negative allosteric stabilize
the T-state of the enzyme. |
|
|
Ans: effectors
Section: 7.3 |
|
20. |
The straight-line kinetic plot of 1/ V0 versus 1/S is called
a . |
|
|
Ans: Lineweaver–Burk plot, or
double-reciprocal plot Section: 7.2 |
Multiple-Choice
Questions
|
21. |
A critical feature of the Michaelis–Menten
model of enzyme catalysis is |
|
|
|
A) |
increasing the probability of product
formation. |
|
|
B) |
shifting the reaction equilibrium. |
|
|
C) |
formation of an ES complex. |
|
|
D) |
All of the above. |
|
|
E) |
None of the above. |
|
|
Ans: C
Section: 7.2 |
|
|
22. |
What value of [S], as a fraction
of KM is required to obtain
20% Vmax? [S] = |
|
|
|
A) |
0.2 KM |
|
|
B) |
0.25 KM |
|
|
C) |
0.5 KM |
|
|
D) |
0.75 KM |
|
|
E) |
0.8 KM |
|
|
Ans: B
Section: 7.2 |
|
|
23. |
Allosteric proteins: |
|
|
|
A) |
contain distinct regulatory sites and
have multiple functional sites. |
|
|
B) |
display cooperativity. |
|
|
C) |
always consist of several identical
subunits. |
|
|
D) |
A and B. |
|
|
E) |
A, B, and C. |
|
|
Ans: D
Section: 7.3 |
|
|
24. |
Allosteric effectors alter the equilibria
between: |
|
|
|
A) |
the ES state. |
|
|
B) |
the R and T forms of a protein. |
|
|
C) |
the forward and reverse reaction rate. |
|
|
D) |
the formation of product and it’s
reverse reaction. |
|
|
E) |
All of the above. |
|
|
Ans: B
Section: 7.3 |
|
|
25. |
The formula V0 = Vmax [S]
, indicates the relationship between [S] + KM |
|
|
|
A) |
the enzyme activity and the equilibrium
constant. |
|
|
B) |
the rate of a catalyzed reaction and
the equilibrium constant. |
|
|
C) |
enzyme activity as a function of substrate
concentration. |
|
|
D) |
All of the above. |
|
|
E) |
None of the above. |
|
|
Ans: C
Section: 7.2 |
|
|
26. |
The model describing allosteric
regulation that requires all subunits to be in the same state is called the
________. |
|
|
|
A) |
concerted model |
|
|
B) |
syncopated model |
|
|
C) |
cooperative model |
|
|
D) |
equilibrium model |
|
|
E) |
None of the above. |
|
|
Ans: A
Section: 7.3 |
|
|
27. |
Loss of allosteric regulation in
the production of purine nucleotides results in ___________. |
|
|
|
A) |
excess nucleotides for DNA |
|
|
B) |
loss of RNA due to ribose phosphate
synthetase |
|
|
C) |
decreased urate degradation |
|
|
D) |
loss in urate concentration |
|
|
E) |
None of the above. |
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Ans: E
Section: 7.3 |
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28. |
The KM is: |
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|
|
A) |
equal to the product concentration at
initial reaction conditions. |
|
|
B) |
equal to the substrate concentration
when the reaction rate is half its maximal value. |
|
|
C) |
proportional to the standard free
energy. |
|
|
D) |
All of the above. |
|
|
E) |
None of the above. |
|
|
Ans: B
Section: 7.2 |
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29. |
Given are five KM values for the
binding of substrates to a particular enzyme. Which has the strongest
affinity when k–1 is greater than k2? |
|
|
A) 150 mM B)
0.15 mM C) 150 mM D) 1.5
nM E) 15,000 pM |
|
|
Ans: D
Section: 7.2 |
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30. |
When substrate concentration is much
greater than KM, the rate of catalysis is
almost equal to |
|
|
A) Kd. B) kcat. C) Vmax. D) All of the
above. E) None of the above. |
|
|
Ans: C
Section: 7.2 |
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31. |
Which of the following is true under
the following conditions: The enzyme concentration is 5 nM, the substrate
concentration is 5 mM, and the KM is 5 mM. |
|
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|
A) |
The enzyme is saturated with substrate. |
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|
B) |
Most of the enzyme does not have
substrate bound. |
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C) |
There is more enzyme than substrate. |
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D) |
All of the above. |
|
|
E) |
None of the above. |
|
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Ans: A
Section: 7.2 |
|
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32. |
Homotrophic effects of allosteric
enzymes: |
|||
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|
A) |
are due to the effects of substrates. |
D) |
shift the kinetics curve to the right. |
|
|
B) |
are due to the effects of allosteric
activators. |
E) |
None of the above. |
|
|
C) |
shift the kinetics curve to the left. |
|
|
|
|
Ans: A
Section: 7.3 |
|||
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33. |
Multiple substrate enzyme reactions are
divided into two classes: |
|
|
|
A) |
sequential reactions and double
displacement reactions. |
|
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B) |
double displacement reactions and
concerted reactions. |
|
|
C) |
sequential reactions and concerted
reactions. |
|
|
D) |
A and C. |
|
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E) |
None of the above. |
|
|
Ans: A
Section: 7.2 |
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34. |
When [S] << KM, the enzymatic velocity
depends on__________. |
|
|
|
A) |
the values of kcat/KM, [S], and [E]t |
|
|
B) |
the Vmax of the reaction |
|
|
C) |
the affinity of the substrate for
the catalytic site |
|
|
D) |
kcat |
|
|
E) |
the formation of the ES complex |
|
|
Ans: A Section: 7.2 |
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|
35. |
Allosteric effectors: |
|
|
|
A) |
can cause large changes in enzymatic
activity. |
|
|
B) |
can lead to a decrease in the
availability of a protein. |
|
|
C) |
do not alter the sensitivity of a
metabolic pathway. |
|
|
D) |
decrease the sensitivity of the enzyme
at nearly all concentrations of substrate. |
|
|
E) |
alter enzyme activity by binding to the
active site of an enzyme. |
|
|
Ans:
A Section: 7.3 |
|
|
36. |
For decades, enzymes have been
studied using ensemble methods, but technology now allows them to be studied
in singulo. Which of the statements below states one of the significant
outcomes of this new technology? |
|
|
|
A) |
New methods better demonstrate cooperativity
of allosteric enzymes. |
|
|
B) |
New methods allow for better
determination of kcat. |
|
|
C) |
New methods reveal a distribution of
enzyme characteristics. |
|
|
D) |
New methods validate the steady-state
assumption of Michaelis–Menten kinetics. |
|
|
E) |
New methods provide understanding of
average enzyme kinetic data. |
|
|
Ans:
C Section: 7.4 |
|
|
37. |
When reaction conditions are such
that the amount of substrate is far greater than the amount of enzyme
present, then the following conditions are also met. |
|
|
|
A) |
The [substrate] is much less than KM. |
|
|
B) |
The V0 is half Vmax. |
|
|
C) |
The enzyme is displaying second-order
kinetics. |
|
|
D) |
The enzyme is displaying first-order
kinetics. |
|
|
E) |
The enzyme is displaying zero-order
kinetics. |
|
|
Ans: E Sections: 7.1
and 7.2 |
|
|
38. |
During the early stages of an
enzyme purification protocol, when cells have been lysed but cytosolic
components have not been separated, the reaction velocity versus substrate
concentration is sigmoidal. As you continue to purify the enzyme, the curve
shifts to the right. Explain your results. |
|
|
|
A) |
This is an enzyme that displays
Michaelis–Menten kinetics, and you purify away a homotrophic inhibitor. |
|
|
B) |
This is an enzyme that displays
Michaelis–Menten kinetics, but you must use a Lineweaver–Burk plot to
determine KM and Vmax correctly. |
|
|
C) |
This is an allosteric enzyme, but you
must use a Lineweaver–Burk plot to determine KM and Vmax correctly. |
|
|
D) |
This is an allosteric enzyme, and
during purification you purify away a heterotrophic activator. |
|
|
E) |
This is an allosteric enzyme displaying
a double-displacement mechanism, and during purification you purify away one
of the substrates. |
|
|
Ans: D
Sections: 7.2 and 7.3 |
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|
39. |
After purifying the enzyme in the
previous question, you determine the Mr to be 75,000. By assaying 5 μg of the
enzyme under saturating [S] concentrations, you determine the Vmax to be 1.68
μmol/sec. Calculate the turnover number for this enzyme. |
|
|
|
A) |
2.25 ´ 106 sec-1 |
|
|
B) |
1.50 ´ 105 sec-1 |
|
|
C) |
2.50 ´ 104 sec-1 |
|
|
D) |
1.79 ´ 105 sec-1 |
|
|
E) |
You need to also know the KM for this enzyme to
calculate turnover number. |
|
|
Ans: D
Section: 7.2 |
|
Short-Answer
Questions
|
40. |
In many enzyme assays, the natural substrate
and product are not used. Why? |
|
|
|
Ans: |
Many products are difficult to measure
accurately. Some are simply difficult to measure, while others are difficult
to discern against the background of other molecules present in the reaction.
Instead, substrates are chosen that the enzyme can still process but that
result in products that can be easily measured. For example, substrates are
chosen that result in products that are colored and can be detected
spectrophotometrically. |
|
|
Section: 7.1 |
|
|
41. |
A protease hydrolyzes the peptide
backbone. What is the substrate(s) and product for this reaction?
Assuming that the concentration of water is so high (~55M) that it does not
appreciably change, to what kind of reaction order would one assign this
reaction? |
|
|
|
Ans: |
The reaction would be Protein + H2O ® peptide-1 +
peptide-2. As water doesn’t significantly change it’s concentration in
an aqueous reaction, the concentration change is zero and can be ignored,
thus the rate of the reaction is directly proportionate to the concentration
of the protein and is a first-order reaction. |
|
|
Section: 7.1 |
|
|
42. |
The rate of a reaction is dependent on
[ES]. Using an enzyme catalyzed reaction scheme, (6), describe the
kinetic model for [ES]. |
|
|
|
Ans: |
The concentration of an ES
complex is described as the enzyme binding to substrate and can be measured
as one kinetic rate constant forming the ES complex. Loss of the ES can
be described as the separation of the two components without reacting (k-1) and the resulting
reaction where ES ® EP ® E + P (k2). |
|
|
Section: 7.2 |
|
|
43. |
Figure 7.8 is a simplified version of a
common set of converging metabolic pathways. Describe the type of
regulation necessary if each of the reactions was reversed and a product, A
or G, were preferred. |
|
|
|
Ans: |
A feed-forward inhibition where a
product, G or H, inhibits e1, e2, e3, or e5. Another possibility is that one
or more of the products A through F inhibits e10 or e11. |
|
|
Section: 7.3 |
|
|
44. |
Draw a Cleland notation for a
sequential reaction and for a double-displacement reaction. |
|
|
|
Ans: |
See Figures 7.6 A and 7.6B. |
|
|
Section: 7.2 |
|
|
45. |
What is the Michaelis–Menten equation?
Define all parameters. |
|
|
|
Ans: |
V0 = Vmax(S/(S + KM)) Initial velocity V0 Maximum velocity Vmax Substrate concentration S Michaelis constant KM |
|
|
Section: 7.2 |
|
|
46. |
What does Vmax indicate? |
|
|
|
Ans: |
The maximum velocity or rate of
reaction as catalyzed by a specific amount of enzyme when it is saturated
with substrate. |
|
|
Section: 7.2 |
|
|
47. |
What is the upper limit of kcat / KM? |
|
|
|
Ans: |
The diffusion-controlled interaction of
the substrate and enzyme determines the upper limit of the rate. The upper
limit is 108 – 109 s-1M-1. |
|
|
Section: 7.2 |
|
|
48. |
How do the intermediate steps in
multi-substrate enzyme mechanisms differ? |
|
|
|
Ans: |
In a sequential displacement reaction,
both substrates bind and a ternary complex of all three is formed. In a
double displacement (ping-pong), one or more products are released prior to
binding of all substrates. Thus, a substituted enzyme intermediate is formed. |
|
|
Section: 7.2 |
|
|
49. |
Describe the difference between the
concerted and the sequential model of allosteric regulation. |
|
|
|
Ans: |
The concerted model describes where a
multi-subunit enzyme can only assume an R or T conformation, whereas the
sequential model assumes that the subunits can assume its conformation
different from the neighboring subunits. In the former, substrate
influences the equilibria between each subunit’s R-T conformation and in the
latter, substrate can have an intermediate impact on affinity and
conformation. |
|
|
Section: 7.3 |
|
|
50. |
Would you expect the order of substrate
binding to be critical for enzyme catalysis? |
|
|
|
Ans: |
Yes, in some cases. For example, in
ping-pong reactions, the proper substrate would have to bind to form the
right substituted enzyme intermediate form. In sequential displacement, both
conditions are observed. Substrates may need to bind in a particular order
(lactate dehydrogenase) or the enzyme may bind substrates and release
products in random order (creatine kinase). |
|
|
Section: 7.2 |
|
|
51. |
What is the turnover number for an
enzyme and what does this value tell us about the enzyme? |
|
|
|
Ans: |
The rate of reaction and dissociation
of the ES complex to E + P is k2. That is the rate at
which an enzyme saturated with substrate converts substrate to product.
This is basically the measure of the reaction without an impact on substrate
binding and is dependent on the concentration of enzyme and describes the
relative speed of a reaction. |
|
|
Section: 7.2 |
|
|
52. |
When designing a drug to inhibit the
formation of a product, which requires several enzymes in a metabolic
pathway, what should be the first piece of information a biochemist needs in
order to develop the drug? |
|
|
|
Ans: |
Find the committed step. In a
metabolic pathway there will be a rate-limiting, committed enzyme step that
is often the target of physiological regulation. This protein would be
the best target for a new drug. |
|
|
Section: 7.2 |
|
|
53. |
How does the sequential model differ
from the concerted model for allosteric enzymes? |
|
|
|
Ans: |
The concerted model does not allow for
anything other than an “all-or-none” complete tense- or relaxed-form protein.
In contrast, the sequential model allows for a mixed type of protein,
containing some tense and some relaxed subunits. The form is in response to
the ligand binding by a particular subunit. |
|
|
Section: 7.3 |
|
|
54. |
Draw a sketch of a Michaelis–Menten
plot and a Lineweaver–Burk plot. Identify how you would determine KM and Vmax from each of
these plots. Explain why the Michaelis–Menten is used more widely than the
Lineweaver–Burk plot even though, in general, straight-line plots are easier
to interpret. |
|
|
|
Ans: |
Sketches should look like Fig 7.3 and
7.5 in the textbook. KM and Vmax should be
identified on the plots. The reason why Lineweaver–Burk plots are rarely used
in enzyme studies is because the data points at high and low concentrations
are weighted differently, making them sensitive to errors. In addition,
computer software has advanced to the point where hyperbolic plots like
Michaelis–Menten plots are much more readily analyzed by computers than they
were originally. |
|
|
Section: 7.2 |
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